GATE EC General Aptitude Previous Year Questions with Solutions

40 General Aptitude questions from the GATE EC 2026 and 2025 and 2024 and 2023 papers, newest first. Try each one, then open its answer: the official answer from that year's key and a worked solution. Each question links to its place in the full paper.

GATE 2026, Q.1

General Aptitude1 markMCQ

Which word is the antonym of nocturnal?

  1. Option A: normal
  2. Option B: diurnal
  3. Option C: abnormal
  4. Option D: exceptional

Full question on page 1 of the official paper (PDF)

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Key idea: Nocturnal means active at night; its opposite is active by day.

Official answer: B

Of the four options, only diurnal, active during the day, is about the time of day at all, so it is the antonym. The others (normal, abnormal, exceptional) have nothing to do with time of day.

See it in the 2026 paper

GATE 2026, Q.2

General Aptitude1 markMCQ

In an exam out of 150: (S1) the highest score is 100; (S2) the fourth highest score is 76; (S3) at least four students scored within 25 marks of each other. Which statement is necessarily correct?

  1. Option A: (S1) and (S2) together imply (S3)
  2. Option B: (S1) and (S3) together imply (S2)
  3. Option C: (S2) and (S3) together imply (S1)
  4. Option D: (S1) implies (S3)

Full question on page 2 of the official paper (PDF)

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Key idea: The top four scores all lie between 76 and 100, a spread of 24.

Official answer: A

Take (S1) and (S2) together. The four highest scores all lie between the fourth highest (76) and the highest (100).

100 - 76 = 24 \le 25

So those four students are within 25 marks of each other, which is (S3). Option (A) holds.

The others fail: (S3) can come from any four students, so it fixes neither the highest score nor the fourth highest, and (S1) alone says nothing about the fourth score.

See it in the 2026 paper

GATE 2026, Q.3

General Aptitude1 markMCQ

Three straight line segments cross a picture whose rectangular middle WXYZ is missing. Which of the four tiles P, Q, R and S completes it?

A picture crossed by three straight line segments, with its rectangular middle WXYZ missing and marked with a question mark. Below it, four candidate tiles P, Q, R and S, each a rectangle WXYZ with three line segments across it in a different arrangement.
Figure from the official GATE 2026 EC paper, IIT Guwahati
  1. Option A: Tile P
  2. Option B: Tile Q
  3. Option C: Tile R
  4. Option D: Tile S

Full question on page 3 of the official paper (PDF)

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Key idea: Match each segment where it enters and leaves the hidden rectangle.

Official answer: D

Follow the stubs outside the rectangle:

  • A segment comes in from the upper left through the top edge and leaves near corner Y, going down to the right.
  • A segment comes in from the upper right through the top edge and leaves through the bottom edge near Z, going down to the left.
  • A nearly horizontal segment enters low on the left edge and leaves higher on the right edge.

Only tile S has all three: two lines crossing from the top edge to the bottom corners, and one shallow line rising from left to right. Tile R has a line starting at corner X, which the stubs don't show. The answer is S, option (D).

See it in the 2026 paper

GATE 2026, Q.4

General Aptitude1 markMCQ

Real numbers yy, pp and nn, all greater than 1, satisfy (log⁡p1/ny)(log⁡y1/np)=16\left(\log_{p^{1/n}} y\right)\left(\log_{y^{1/n}} p\right) = 16. Find nn.

  1. Option A: 2
  2. Option B: 4
  3. Option C: 8
  4. Option D: 16

Full question on page 4 of the official paper (PDF)

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Key idea: Taking the nth root of a base multiplies the logarithm by n.

Official answer: B

Change both logarithms to plain \log:

\log_{p^{1/n}} y = \frac{\log y}{\tfrac{1}{n}\log p} = n \log_p y, \qquad \log_{y^{1/n}} p = n \log_y p
\begin{aligned} \log_{p^{1/n}} y &= \frac{\log y}{\tfrac{1}{n}\log p} \\ &= n \log_p y, \\ \log_{y^{1/n}} p &= n \log_y p \end{aligned}

Since \log_p y \cdot \log_y p = 1, the product is n^2 = 16, so n = 4 (all quantities exceed 1, so n > 0). Option (B).

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See it in the 2026 paper

GATE 2026, Q.5

General Aptitude1 markMCQ

The statement for each of 100 students, there is another student whose score is at most 10 marks away is false. Which statement must be true?

  1. Option A: For each student, every other student's score is more than 10 marks away.
  2. Option B: At least one student has every other student's score more than 10 marks away.
  3. Option C: Exactly one student has some scores more than 10 marks away.
  4. Option D: For each student, exactly one other student's score is more than 10 marks away.

Full question on page 5 of the official paper (PDF)

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Key idea: Negating for every ... there exists gives there exists ... for every.

Official answer: B

Apply it to the statement: for every student becomes there exists a student, and there exists another student within 10 marks becomes every other student is more than 10 marks away.

That is option (B). Options (A) and (D) make claims about every student, and (C) says exactly one, neither of which follows from the negation.

See it in the 2026 paper

GATE 2026, Q.6

General Aptitude2 marksMCQ

Solve four clue words: a synonym of recognize (8 letters, _D_NT_FY), a story long enough to fill a book (5, ___EL), two of something (6, ___PLE), one of two equal parts (4, ___F). Their first letters rearrange into which four-letter word?

  1. Option A: CHIN
  2. Option B: COIN
  3. Option C: ITCH
  4. Option D: NOSE

Full question on page 6 of the official paper (PDF)

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Key idea: Solve the clues first, then rearrange the four first letters.

Official answer: A

  • Synonym of recognize, 8 letters: IDENTIFY.
  • A story long enough for a book, 5 letters: NOVEL.
  • Two of something, 6 letters: COUPLE.
  • One of two equal parts, 4 letters: HALF.

The first letters I, N, C, H rearrange to CHIN. Option (A).

See it in the 2026 paper

GATE 2026, Q.7

General Aptitude2 marksMCQ

Children P, Q, R and parents X, Y play doubles. X and Y each have a different child playing, so exactly one child has no parent playing. A parent and their child never play on the same team, and a match has at most one parent-child pair. Matches: P and X vs Q and R; P and R vs X and Y; R and X vs Q and Y. Which is correct?

  1. Option A: P does not have a parent playing
  2. Option B: Q does not have a parent playing
  3. Option C: R does not have a parent playing
  4. Option D: X does not have a child playing

Full question on page 7 of the official paper (PDF)

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Key idea: Teammates can't be parent and child, and a match can't hold two parent-child pairs.

Official answer: C

Look at who plays together in each match:

  • Match 1 (P and X together): X is not P's parent.
  • Match 3 (R and X together, Q and Y together): X is not R's parent, and Y is not Q's parent.

So X's child is Q, and Y's child is P or R.

Rule (ii) allows at most one parent-child pair in a match. Match 3 already has X against Q. If Y were R's parent, match 3 would also have Y against R: two pairs. So Y is P's parent, and R has no parent playing. Option (C).

See it in the 2026 paper

GATE 2026, Q.8

General Aptitude2 marksMCQ

PkP_k is the perimeter of a square of side kk. Find P1+P2+⋯+P10P_1 + P_2 + \cdots + P_{10}.

  1. Option A: 55
  2. Option B: 110
  3. Option C: 220
  4. Option D: 440

Full question on page 8 of the official paper (PDF)

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Key idea: P_k = 4k, so the sum is 4 times the sum of 1 to 10.

Official answer: C

P_k = 4k \;\Rightarrow\; \sum_{k=1}^{10} 4k = 4 \cdot \frac{10 \cdot 11}{2} = 220
\begin{aligned} P_k &= 4k \\ &\Rightarrow\; \sum_{k=1}^{10} 4k \\ &\quad = 4 \cdot \frac{10 \cdot 11}{2} \\ &\quad = 220 \end{aligned}

Option (C).

See it in the 2026 paper

GATE 2026, Q.9

General Aptitude2 marksMCQ

Atlantis is an island of radius 2.5 stades, surrounded by rings of water 1, land 2, water 2, land 3 and water 3 stades wide. Find the ratio of land area to water area.

Concentric circles: a central Inner Island, then alternating rings of water (white) and land (shaded), with points A to F marking the ring boundaries along a radius.
Figure from the official GATE 2026 EC paper, IIT Guwahati
  1. Option A: 0.45
  2. Option B: 0.60
  3. Option C: 0.75
  4. Option D: 0.90

Full question on page 9 of the official paper (PDF)

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Key idea: Every ring's area is \pi(R^2 - r^2), so \pi cancels in the ratio.

Official answer: C

The boundaries are at radii 2.5, 3.5, 5.5, 7.5, 10.5 and 13.5. Every area is \pi times a difference of squares, so \pi cancels:

\text{Land} \propto 2.5^2 + (5.5^2 - 3.5^2) + (10.5^2 - 7.5^2) = 6.25 + 18 + 54 = 78.25
\begin{aligned} \text{Land} &\propto 2.5^2 \\ &\quad + (5.5^2 - 3.5^2) \\ &\quad + (10.5^2 - 7.5^2) \\ &= 6.25 + 18 + 54 \\ &= 78.25 \end{aligned}
\text{Water} \propto (3.5^2 - 2.5^2) + (7.5^2 - 5.5^2) + (13.5^2 - 10.5^2) = 6 + 26 + 72 = 104
\begin{aligned} \text{Water} &\propto (3.5^2 - 2.5^2) \\ &\quad + (7.5^2 - 5.5^2) \\ &\quad + (13.5^2 - 10.5^2) \\ &= 6 + 26 + 72 \\ &= 104 \end{aligned}

The ratio is 78.25 / 104 \approx 0.75. Option (C).

See it in the 2026 paper

GATE 2026, Q.10

General Aptitude2 marksMCQ

The example shows how the two-line block Ref Fig / 12 34 is transformed. Which of the tiles P, Q, R and S applies the same transformation to the block GATE - 2026 / Aptitude Test?

The example block Ref Fig over 12 34 becomes 12 34 over Ref Fig, each line flipped upside down. Below, the block GATE - 2026 over Aptitude Test with a question mark, and four tiles P, Q, R and S showing that block with its lines swapped, flipped or mirrored in different ways.
Figure from the official GATE 2026 EC paper, IIT Guwahati
  1. Option A: Tile P
  2. Option B: Tile Q
  3. Option C: Tile R
  4. Option D: Tile S

Full question on page 10 of the official paper (PDF)

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Key idea: The example is a reflection in a horizontal mirror.

Official answer: C

In the example, the two lines swap places and every character is flipped upside down, while each line still runs left to right. That is a reflection in a horizontal mirror.

Applied to the new block, the second line moves to the top and both lines appear upside down but in their original left-to-right order. Tile R shows exactly that. P also swaps the two words of one line, Q swaps the parts of the other line, and S does both, which the example never does. Option (C).

See it in the 2026 paper

GATE 2025, Q.1

General Aptitude1 markMCQ

Group I lists words in decreasing order of intensity: Abuse, Insult, Ridicule. Group II follows the same pattern: ____, Praise, Appreciate. Which word fills the gap?

  1. Option A: Extol
  2. Option B: Prize
  3. Option C: Appropriate
  4. Option D: Espouse

Full question on page 1 of the official paper (PDF)

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Key idea: The missing word has to be a stronger form of approval than the two after it.

Official answer: A

Group I goes from the harshest criticism to the mildest, so Group II must go from the warmest approval down to appreciation. To extol is to praise very highly, which fits before praise.

Prize means to value something, appropriate means to take or to be suitable, and espouse means to adopt a cause. None of them is a degree of praise. Option (A).

See it in the 2025 paper

GATE 2025, Q.2

General Aptitude1 markMCQ

Choose the best completion: "Had I learnt acting as a child, I ____ a famous film star."

  1. Option A: will be
  2. Option B: can be
  3. Option C: am going to be
  4. Option D: could have been

Full question on page 1 of the official paper (PDF)

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Key idea: A condition about the past that didn't happen takes a result with a modal plus have and a past participle.

Official answer: D

Had I learnt is the inverted form of if I had learnt: the speaker didn't learn acting as a child. The result of an unreal past condition is written with would have, could have or might have and a past participle, so could have been is right.

The other three are present or future forms, which don't match a condition that is already over. Option (D).

See it in the 2025 paper

GATE 2025, Q.3

General Aptitude1 markMCQ

The 12 notes C, C#, D, D#, E, F, F#, G, G#, A, A# and B rise in frequency by a factor of 212\sqrt[12]{2} from each note to the next. If C is at 130.8 Hz, what is the ratio of the frequencies of F# and C?

  1. Option A: 26\sqrt[6]{2}
  2. Option B: 2\sqrt{2}
  3. Option C: 24\sqrt[4]{2}
  4. Option D: 22

Full question on page 2 of the official paper (PDF)

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Key idea: A fixed ratio per step means the ratio over several steps is that factor raised to the number of steps.

Official answer: B

From C, the notes C#, D, D#, E, F and F# are six steps up. Six steps multiply the frequency by

\left(2^{1/12}\right)^{6} = 2^{6/12} = 2^{1/2} = \sqrt{2}
\begin{aligned} \left(2^{1/12}\right)^{6} &= 2^{6/12} \\ &= 2^{1/2} \\ &= \sqrt{2} \end{aligned}

The 130.8 Hz isn't needed, because a ratio doesn't depend on where the scale starts. Option (B).

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GATE 2025, Q.4

General Aptitude1 markMCQ

A curve is drawn by an iterative algorithm. Iteration 0 is a straight segment of length 1. The figure shows iterations 1 and 2, whose segments are each 13\tfrac{1}{3} and 19\tfrac{1}{9} long. What is the total length of the curve after iteration nn?

Three stages of a curve. Iteration 0: a horizontal segment of length 1. Iteration 1: five segments of length 1/3, a flat piece, a step up, a flat top, a step down and a flat piece. Iteration 2: the same shape applied to each of those five segments, giving 25 segments of length 1/9.
Figure from the official GATE 2025 EC paper, IIT Roorkee
  1. Option A: (53)n/2\left(\tfrac{5}{3}\right)^{n/2}
  2. Option B: (53)n\left(\tfrac{5}{3}\right)^{n}
  3. Option C: (53)2n\left(\tfrac{5}{3}\right)^{2n}
  4. Option D: (53)n(2n−1)\left(\tfrac{5}{3}\right)^{n(2n-1)}

Full question on page 3 of the official paper (PDF)

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Key idea: Find what one iteration does to the total length; a constant factor per iteration gives a power of n.

Official answer: B

Count the segments in the figure. Iteration 1 has 5 segments of \tfrac{1}{3}, so its length is \tfrac{5}{3}. Iteration 2 replaces each of those by 5 segments a third as long: 25 segments of \tfrac{1}{9}, length \tfrac{25}{9}.

Every iteration multiplies the number of segments by 5 and divides their length by 3, so the length grows by \tfrac{5}{3} each time:

L_n = \left(\frac{5}{3}\right)^{n}

Only (B) gives \tfrac{5}{3} at n = 1 and \tfrac{25}{9} at n = 2. Option (B).

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GATE 2025, Q.5

General Aptitude1 markMCQ

Which of the four plots in the figure represents f(x)=−∣x∣xf(x) = -\dfrac{|x|}{x}, where xx is a non-zero real number?

Four plots labelled A to D. A: f(x) is 1 for negative x and -1 for positive x, with (0,1) and (0,-1) marked. B: f(x) is -1 for negative x and 1 for positive x. C: a vertical line up from (-1,0) and a vertical line down from (1,0). D: a curve rising steeply toward (0,1) from the left, and a curve rising from (0,-1) toward zero on the right.
Figure from the official GATE 2025 EC paper, IIT Roorkee
  1. Option A: Plot (A)
  2. Option B: Plot (B)
  3. Option C: Plot (C)
  4. Option D: Plot (D)

Full question on page 4 of the official paper (PDF)

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Key idea: Treat positive and negative x separately, since |x| is x for one and -x for the other.

Official answer: A

For x > 0, |x| = x and f(x) = -1. For x < 0, |x| = -x and f(x) = +1. So the graph is the constant 1 left of the axis and the constant -1 right of it, with no value at x = 0.

That is plot (A). Plot (B) is the reverse, +|x|/x, and (C) and (D) aren't constant on either side. Option (A).

See it in the 2025 paper

GATE 2025, Q.6

General Aptitude2 marksMCQ

Arrange the sentences into a coherent paragraph. P: Over time, such adaptations lead to large evolutionary changes that can shape new species. Q: In the natural world, organisms constantly adapt to their environments. R: This process of adaptation is driven by natural selection, in which favourable traits improve survival and reproduction. S: As environments change, organisms that can adapt their behaviour, structure and physiology are more likely to survive.

  1. Option A: P, Q, R, S
  2. Option B: Q, S, R, P
  3. Option C: R, S, Q, P
  4. Option D: S, P, R, Q

Full question on page 5 of the official paper (PDF)

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Key idea: Start with the sentence that refers back to nothing, then follow words such as this and such, which point to an earlier sentence.

Official answer: B

Q introduces the topic and leans on nothing before it, so it opens. S explains how adapting helps organisms survive as environments change.

R then names this process of adaptation as natural selection, and P, with such adaptations and over time, closes on the long-term result. The order Q, S, R, P is option (B).

The other orders put P or R, which both point back to something already said, ahead of Q.

See it in the 2025 paper

GATE 2025, Q.7

General Aptitude2 marksMCQ

A stick 1 m long is broken at distances b1b_1 and b2b_2 from one end, with 0<b1<b2<10 < b_1 < b_2 < 1. Which of these is NOT a necessary condition for the three pieces to form a triangle?

  1. Option A: b1<0.5b_1 < 0.5
  2. Option B: b2>0.5b_2 > 0.5
  3. Option C: b2<b1+0.5b_2 < b_1 + 0.5
  4. Option D: b1+b2<1b_1 + b_2 < 1

Full question on page 6 of the official paper (PDF)

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Key idea: Three lengths with a fixed total make a triangle exactly when each one is less than half the total.

Official answer: D

The pieces are b_1, b_2 - b_1 and 1 - b_2, which add up to 1. Each must be shorter than the other two together, that is, shorter than 0.5:

b_1 < 0.5, \qquad b_2 - b_1 < 0.5, \qquad 1 - b_2 < 0.5 \;\Rightarrow\; b_2 > 0.5
\begin{aligned} b_1 &< 0.5, \\ b_2 - b_1 &< 0.5, \\ 1 - b_2 &< 0.5 \\ \Rightarrow\; b_2 &> 0.5 \end{aligned}

Those are (A), (C) and (B). Condition (D) isn't needed: b_1 = 0.4 and b_2 = 0.7 give pieces of 0.4, 0.3 and 0.3, a valid triangle, yet b_1 + b_2 = 1.1. Option (D).

See it in the 2025 paper

GATE 2025, Q.8

General Aptitude2 marksMCQ

Eight students start in a circle, clockwise P, R, T, Q, S, V, U, W, and move forward clockwise as they play musical chairs. After round 1 the 4th student behind P leaves; after round 2, the 5th behind Q; after round 3, the 3rd behind V; after round 4, the 4th behind U. Who is left after round 4?

  1. Option A: P, T, Q, S
  2. Option B: V, P, T, Q
  3. Option C: W, R, Q, V
  4. Option D: Q, T, V, W

Full question on page 7 of the official paper (PDF)

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Key idea: A question given marks to all scores full marks for every candidate, whatever they answered.

Official answer: Marks to all

The final key awards marks to all for this question, and doesn't say why. We don't give an answer: as printed, the question doesn't say how far the students move in a round, or which way round the circle counts as behind, and the student who leaves each round depends on both.

In the exam this meant there was nothing to lose by answering it. As practice, treat it as an exercise in reading a puzzle's rules carefully before starting.

Ruling in the key: The final key gives marks to all (MTA) for this question: every candidate received its 2 marks.

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GATE 2025, Q.9

General Aptitude2 marksMCQ

A table gives the gold, silver and bronze medals of the top five nations by golds: USA 40, 44, 41; Canada 39, 27, 24; Japan 20, 12, 13; Australia 17, 19, 16; France 16, 26, 22. Based only on these figures, which statement is INCORRECT?

  1. Option A: France would be third if the list were ordered by total medals.
  2. Option B: The top two nations would stay in the same order if the list were ordered by total medals.
  3. Option C: USA and Canada together have less than 50% of the medals won by the nations in the table.
  4. Option D: Canada has won twice as many medals in total as Japan.

Full question on page 8 of the official paper (PDF)

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Key idea: Every statement is about totals, so total each nation's medals first.

Official answer: C

Adding gold, silver and bronze:

  • USA: 125
  • Canada: 90
  • France: 64
  • Australia: 52
  • Japan: 45
  • All five: 376

(A) is true: France's 64 is third, ahead of Australia and Japan. (B) is true: the USA stays ahead of Canada. (D) is true: 90 is twice 45.

(C) is false: the USA and Canada have 215 of the 376 medals, about 57%, which is more than half. Option (C).

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GATE 2025, Q.10

General Aptitude2 marksMCQ

An organisation charges an overhead on a consulting fee: 20% of the fee for fees up to ₹5,00,000, and for higher fees ₹1,00,000 plus 10% of the amount above ₹5,00,000. GST of 18% is charged on the fee plus the overhead, and the client pays the fee, overhead and GST. If the client can pay at most ₹10,00,000, what is the largest fee the employee can charge?

  1. Option A: ₹7,01,438
  2. Option B: ₹7,24,961
  3. Option C: ₹7,51,232
  4. Option D: ₹7,75,784

Full question on page 9 of the official paper (PDF)

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Key idea: With a slab rule, decide which slab the answer is in, then solve the single linear equation for that slab.

Official answer: B

At a fee of ₹5,00,000 the client pays 1.18 \times 1.2 \times 5{,}00{,}000 = 7{,}08{,}000 rupees, well under the limit, so the fee is in the upper slab. There, with the fee F in rupees, the overhead and the client's total are

O = 1{,}00{,}000 + 0.1\,(F - 5{,}00{,}000) = 0.1F + 50{,}000
\begin{aligned} O &= 1{,}00{,}000 \\ &\quad + 0.1\,(F - 5{,}00{,}000) \\ &= 0.1F + 50{,}000 \end{aligned}
1.18\,(F + O) = 1.18\,(1.1F + 50{,}000) \le 10{,}00{,}000
\begin{aligned} &1.18\,(F + O) \\ &\quad = 1.18\,(1.1F + 50{,}000) \\ &\quad \le 10{,}00{,}000 \end{aligned}
F \le \frac{10{,}00{,}000 / 1.18 - 50{,}000}{1.1} \approx 7{,}24{,}961.5
\begin{aligned} F &\le \frac{10{,}00{,}000 / 1.18 - 50{,}000}{1.1} \\ &\approx 7{,}24{,}961.5 \end{aligned}

The largest fee is ₹7,24,961. Option (B).

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GATE 2024, Q.1

General Aptitude1 markMCQ

If → means increasing intensity, then [charm → enamor → bewitch] is analogous to [bored → ____ → weary]. Which word fills the blank?

  1. Option A: jaded
  2. Option B: baffled
  3. Option C: dead
  4. Option D: worsted

Full question on page 1 of the official paper (PDF)

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Key idea: The missing word must be a stronger kind of boredom than bored, but milder than weary.

Official answer: A

Each step in the first group is a stronger version of the same feeling. Jaded means tired and dulled by too much of something, which sits between being bored and being weary of it.

Baffled is confusion, dead isn't a degree of boredom, and worsted means defeated. Option (A).

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GATE 2024, Q.2

General Aptitude1 markMCQ

P, Q, R, S and T share an office of three rooms. Two of them are siblings, and siblings must not share a room. S and Q are single children. Two acceptable allocations are: rooms {P, R}, {T, S}, {Q}; and rooms {P, Q}, {R, T}, {S}. Who are the siblings?

  1. Option A: P and T
  2. Option B: P and S
  3. Option C: T and Q
  4. Option D: T and R

Full question on page 2 of the official paper (PDF)

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Key idea: Anyone who shares a room in an acceptable allocation can't be the sibling pair.

Official answer: A

S and Q have no siblings, so the pair is two of P, R and T. Pairs that share a room in an acceptable allocation are ruled out: P and R (first allocation) and R and T (second).

That leaves P and T. Option (A).

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GATE 2024, Q.3

General Aptitude1 markMCQ

Five years ago, the ratio of Aman's age to his father's was 1 : 4. Five years from now it will be 2 : 5. How old was his father when Aman was born?

  1. Option A: 28 years
  2. Option B: 30 years
  3. Option C: 35 years
  4. Option D: 32 years

Full question on page 3 of the official paper (PDF)

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Key idea: Write the two ratios as two linear equations in the present ages.

Official answer: B

With present ages a and f:

f - 5 = 4(a - 5), \qquad 5(a + 5) = 2(f + 5)
\begin{aligned} f - 5 &= 4(a - 5), \\ 5(a + 5) &= 2(f + 5) \end{aligned}

The first gives f = 4a - 15. Substituting, 5a + 25 = 8a - 20, so a = 15 and f = 45. The father was 45 - 15 = 30 when Aman was born. Option (B).

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GATE 2024, Q.4

General Aptitude1 markMCQ

For a real number x>1x > 1, 1log⁡2x+1log⁡3x+1log⁡4x=1\dfrac{1}{\log_2 x} + \dfrac{1}{\log_3 x} + \dfrac{1}{\log_4 x} = 1. What is xx?

  1. Option A: 4
  2. Option B: 12
  3. Option C: 24
  4. Option D: 36

Full question on page 3 of the official paper (PDF)

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Key idea: 1/\log_b x = \log_x b, which turns the sum into a single logarithm.

Official answer: C

\log_x 2 + \log_x 3 + \log_x 4 = \log_x (2 \times 3 \times 4) = \log_x 24 = 1
\begin{aligned} &\log_x 2 + \log_x 3 + \log_x 4 \\ &\quad = \log_x (2 \times 3 \times 4) \\ &\quad = \log_x 24 \\ &\quad = 1 \end{aligned}

So x = 24. Option (C).

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GATE 2024, Q.5

General Aptitude1 markMCQ

What is the greatest prime factor of 3199−31963^{199} - 3^{196}?

  1. Option A: 13
  2. Option B: 17
  3. Option C: 3
  4. Option D: 11

Full question on page 4 of the official paper (PDF)

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Key idea: Take out the common power of 3 first.

Official answer: A

3^{199} - 3^{196} = 3^{196}(3^3 - 1) = 3^{196} \times 26 = 2 \times 3^{196} \times 13
\begin{aligned} 3^{199} - 3^{196} &= 3^{196}(3^3 - 1) \\ &= 3^{196} \times 26 \\ &= 2 \times 3^{196} \times 13 \end{aligned}

The prime factors are 2, 3 and 13, so the greatest is 13. Option (A).

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GATE 2024, Q.6

General Aptitude2 marksMCQ

Order the sentences into a coherent passage. P: Shifu's student exclaimed, "Why do you run since the bull is an illusion?" Q: Shifu said, "Surely my running away from the bull is also an illusion." R: Shifu once proclaimed that all life is illusion. S: One day, when a bull gave him chase, Shifu began running for his life.

  1. Option A: SPRQ
  2. Option B: SRPQ
  3. Option C: RSPQ
  4. Option D: RPQS

Full question on page 5 of the official paper (PDF)

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Key idea: Set up the claim before the incident that tests it, and end on the reply to the question.

Official answer: C

R states Shifu's belief, so it comes first. S is the incident, P is the student's challenge, which needs both R and S before it, and Q is Shifu's reply to P. The order is R, S, P, Q. Option (C).

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GATE 2024, Q.7

General Aptitude2 marksMCQ

Four identical cylindrical chalk sticks, each of radius r=0.5r = 0.5 cm and length l=10l = 10 cm, are bound tightly in a 2 × 2 bundle with duct tape as wide as the sticks are long, as in the figure. What area of tape, in cm², wraps the bundle once?

Four identical cylinders of radius r arranged two by two and wrapped in tape along their length l.
Figure from the official GATE 2024 EC paper, IISc Bengaluru
  1. Option A: 20(4+π)20(4 + \pi)
  2. Option B: 20(8+π)20(8 + \pi)
  3. Option C: 10(8+π)10(8 + \pi)
  4. Option D: 10(4+π)10(4 + \pi)

Full question on page 6 of the official paper (PDF)

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Key idea: A tight band round circles in a square is four straight runs plus one full circle's worth of arcs.

Official answer: D

Around the bundle, the tape runs straight along each side for one diameter, 2r = 1 cm, between the outer sticks, and curves round each corner stick through a quarter turn. The four quarter turns make one full circle:

\text{perimeter} = 4(2r) + 2\pi r = 4 + \pi\ \text{cm}
\begin{aligned} \text{perimeter} &= 4(2r) + 2\pi r \\ &= 4 + \pi\ \text{cm} \end{aligned}

The tape is 10 cm wide, so its area is 10(4 + \pi) cm². Option (D).

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GATE 2024, Q.8

General Aptitude2 marksMCQ

The bar chart in the figure shows the percentage of the population in each BMI category in 2003 and 2023. Which statement is INCORRECT?

Horizontal bar chart of percentage of population by BMI category. 2023: obese 25%, overweight 40%, normal 30%, underweight 5%. 2003: obese 15%, overweight 25%, normal 50%, underweight 10%.
Figure from the official GATE 2024 EC paper, IISc Bengaluru
  1. Option A: The ratio of overweight to normal has increased in 20 years.
  2. Option B: The ratio of underweight to normal has decreased in 20 years.
  3. Option C: The ratio of obese to normal has decreased in 20 years.
  4. Option D: The percentage in the normal category has decreased in 20 years.

Full question on page 7 of the official paper (PDF)

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Key idea: Read the eight values off the chart once, then compare each ratio across the two years.

Official answer: C

From the chart, 2003 has obese 15%, overweight 25%, normal 50% and underweight 10%; 2023 has 25%, 40%, 30% and 5%.

  • (A) Overweight to normal: 0.5 in 2003, 1.33 in 2023. Increased: correct.
  • (B) Underweight to normal: 0.2, then 0.17. Decreased: correct.
  • (C) Obese to normal: 0.3, then 0.83. It increased, so this statement is INCORRECT.
  • (D) Normal: 50%, then 30%. Decreased: correct.

Option (C).

See it in the 2024 paper

GATE 2024, Q.9

General Aptitude2 marksMCQ

The figure shows examples of a mirror reflection and a water reflection. An object, reflected first in a mirror and then in water, appears as the seven-segment image 5:24. Which option is the original object?

Examples: a mirror reflection of a seven-segment 6 and a water reflection of a 6. Then the image 5:24, and four candidate originals A to D drawn in seven-segment digits: A reads h2:5, B reads 2:5H, C reads H5:2, D reads h:25.
Figure from the official GATE 2024 EC paper, IISc Bengaluru
  1. Option A: Option (A)
  2. Option B: Option (B)
  3. Option C: Option (C)
  4. Option D: Option (D)

Full question on page 8 of the official paper (PDF)

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Key idea: A mirror flips left to right and water flips top to bottom; together they turn the image through 180 degrees.

Official answer: A

Undoing both reflections means rotating the image 5:24 through 180°. The order of the characters reverses, and each turns upside down: 4 becomes an h, while 2 and 5 look the same rotated.

So the original reads h, 2, a colon, then 5, which is option (A).

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GATE 2024, Q.10

General Aptitude2 marksMCQ

Sheets A and B are each 24 cm × 16 cm. Fold FO1 halves a sheet with the fold parallel to the original long edge; FO2 halves it with the fold parallel to the original short edge. Sheet A is folded twice by FO1 and sheet B twice by FO2. What is the ratio of the perimeters of A and B?

  1. Option A: 14 : 11
  2. Option B: 11 : 14
  3. Option C: 18 : 11
  4. Option D: 11 : 18

Full question on page 9 of the official paper (PDF)

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Key idea: Each fold halves only the side perpendicular to the fold line.

Official answer: A

FO1 folds parallel to the 24 cm edge, so it halves the 16 cm side: after two folds A is 24 × 4 cm, perimeter 56 cm. FO2 halves the 24 cm side: B is 6 × 16 cm, perimeter 44 cm.

56 : 44 = 14 : 11

Option (A).

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GATE 2023, Q.1

General Aptitude1 markMCQ

"I cannot support this proposal. My ________ will not permit it." Which word fills the blank?

  1. Option A: conscious
  2. Option B: consensus
  3. Option C: conscience
  4. Option D: consent

Full question on page 1 of the official paper (PDF)

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Key idea: The blank needs a noun for an inner moral sense, the thing that permits or forbids.

Official answer: C

A conscience is a person's sense of right and wrong, and it is what would or wouldn't permit supporting a proposal.

Conscious is an adjective, consensus is a group's agreement, not one person's, and consent is permission given, which doesn't itself permit anything. Option (C).

See it in the 2023 paper

GATE 2023, Q.2

General Aptitude1 markMCQ

Courts : ________ : : Parliament : Legislature (by word meaning). Which word fills the blank?

  1. Option A: Judiciary
  2. Option B: Executive
  3. Option C: Governmental
  4. Option D: Legal

Full question on page 1 of the official paper (PDF)

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Key idea: Parliament is the body that makes up the legislature; find the branch that courts make up.

Official answer: A

Parliament belongs to the legislature, the law-making branch. Courts belong to the judiciary, the branch that interprets and applies the law. Option (A).

The executive is the third branch, and governmental and legal are adjectives, not branches.

See it in the 2023 paper

GATE 2023, Q.3

General Aptitude1 markMCQ

What is the smallest number with distinct digits whose digits add up to 45?

  1. Option A: 123555789
  2. Option B: 123457869
  3. Option C: 123456789
  4. Option D: 99999

Full question on page 2 of the official paper (PDF)

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Key idea: 0 to 9 add up to 45, so the digits must be 1 to 9 (a 0 adds nothing and can't lead), placed in rising order.

Official answer: C

The digits 0 to 9 add up to 45. A number with distinct digits summing to 45 must therefore use 1 to 9 (adding 0 only makes it longer, so bigger). The smallest arrangement puts them in rising order: 123456789.

(A) repeats the 5 and (D) repeats the 9, so neither has distinct digits, and (B) uses the right digits in a larger order. Option (C).

See it in the 2023 paper

GATE 2023, Q.4

General Aptitude1 markMCQ

In a class of 100 students, (i) 30 students like neither romantic movies nor comedy movies, (ii) the number who like romantic movies is twice the number who like comedy movies, and (iii) 20 students like both. How many students like romantic movies?

  1. Option A: 40
  2. Option B: 20
  3. Option C: 60
  4. Option D: 30

Full question on page 2 of the official paper (PDF)

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Key idea: Students who like at least one kind: n(R \cup C) = n(R) + n(C) - n(R \cap C).

Official answer: C

Taking away the 30 who like neither leaves 100 - 30 = 70 in the union. With n(C) = c and n(R) = 2c:

2c + c - 20 = 70 \quad\Rightarrow\quad c = 30,\quad n(R) = 60
\begin{aligned} 2c + c - 20 &= 70 \\ \Rightarrow\; \\ c &= 30, \\ n(R) &= 60 \end{aligned}

Option (C).

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GATE 2023, Q.5

General Aptitude1 markMCQ

How many rectangles are present in the figure? It is a square with both diagonals drawn and a tilted square joining the midpoints of its sides.

A square with both of its diagonals and a tilted square joining the midpoints of its four sides, forming a lattice of diamonds.
Figure from the official GATE 2023 EC paper, IIT Kanpur
  1. Option A: 8
  2. Option B: 9
  3. Option C: 10
  4. Option D: 12

Full question on page 3 of the official paper (PDF)

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Key idea: Apart from the outer square, every rectangle is tilted: its sides lie on the three lines of each diagonal direction.

Official answer: C

Inside the square there are three parallel lines in each diagonal direction: the diagonal itself and the two sides of the inner tilted square. A tilted rectangle needs two lines from each direction, and every such choice has all four corners inside the outer square:

\binom{3}{2} \times \binom{3}{2} = 9

These are the four small squares, the four rectangles made of two small squares, and the inner tilted square. With the outer square, 9 + 1 = 10. Option (C).

See it in the 2023 paper

GATE 2023, Q.6

General Aptitude2 marksMCQ

Forestland is a planet inhabited by different kinds of creatures. Among other creatures, it is populated by animals all of whom are ferocious. There are also creatures that have claws, and some that do not. All creatures that have claws are ferocious. Based only on this information, which option can be logically inferred with certainty?

  1. Option A: All creatures with claws are animals.
  2. Option B: Some creatures with claws are non-ferocious.
  3. Option C: Some non-ferocious creatures have claws.
  4. Option D: Some ferocious creatures are creatures with claws.

Full question on page 4 of the official paper (PDF)

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Key idea: Clawed creatures exist and all of them are ferocious, so the two sets overlap.

Official answer: D

Creatures with claws exist, and every one of them is ferocious, so at least some ferocious creatures have claws: (D) follows.

(B) and (C) contradict "all creatures that have claws are ferocious", and (A) isn't stated: a clawed creature could be ferocious without being an animal. Option (D).

See it in the 2023 paper

GATE 2023, Q.7

General Aptitude2 marksMCQ

Which one of the following options represents the graph in the figure?

Graph of f(x): zero at x = 0, rising to a peak on each side of the origin, symmetric about the vertical axis, and decaying towards zero far from the origin on both sides.
Figure from the official GATE 2023 EC paper, IIT Kanpur
  1. Option A: f(x)=x2 2−∣x∣f(x) = x^2\, 2^{-|x|}
  2. Option B: f(x)=x 2−∣x∣f(x) = x\, 2^{-|x|}
  3. Option C: f(x)=∣x∣ 2−xf(x) = |x|\, 2^{-x}
  4. Option D: f(x)=x 2−xf(x) = x\, 2^{-x}

Full question on page 5 of the official paper (PDF)

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Key idea: The graph is symmetric about the y-axis and never negative, so f must be even and non-negative.

Official answer: A

Test each option for an even, non-negative function:

  • (A) x^2 2^{-|x|}: even, zero at 0, positive elsewhere, and decays as |x| grows. It matches.
  • (B) x\, 2^{-|x|} is odd: negative for x < 0.
  • (C) |x|\, 2^{-x} grows without bound as x \to -\infty.
  • (D) x\, 2^{-x} is negative for x < 0 and grows in size as x \to -\infty.

Option (A). Its peaks are where 2x - x^2 \ln 2 = 0, at x = \pm 2/\ln 2 \approx \pm 2.885.

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GATE 2023, Q.8

General Aptitude2 marksMCQ

Which one of the following options can be inferred from the passage alone? "When I was a kid, I was partial to stories about other worlds and interplanetary travel. I used to imagine that I could just gaze off into space and be whisked to another planet." [Excerpt from The Truth about Stories by T. King]

  1. Option A: It is a child's description of what he or she likes.
  2. Option B: It is an adult's memory of what he or she liked as a child.
  3. Option C: The child in the passage read stories about interplanetary travel only in parts.
  4. Option D: It teaches us that stories are good for children.

Full question on page 6 of the official paper (PDF)

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Key idea: "When I was a kid" and the past tense mean the speaker is no longer a child.

Official answer: B

The narrator looks back ("When I was a kid", "I used to imagine"), so this is an adult remembering a childhood liking. Option (B).

(A) needs the speaker to be a child now. Partial to means fond of, not reading in parts, so (C) misreads it, and the passage draws no lesson, so (D) goes beyond it.

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GATE 2023, Q.9

General Aptitude2 marksMCQ

Out of 1000 individuals in a town, 100 unidentified individuals are covid positive. To identify them with few testing kits, the authorities (i) collect saliva samples from all 1000 and randomly group them into sets of 5, (ii) mix the samples in each set and test the mixed sample, (iii) if that test is negative, declare all 5 negative, and (iv) if it is positive, test all 5 separately. With this strategy, no more than ____ testing kits will be required to identify all 100 positives, however they are grouped.

  1. Option A: 700
  2. Option B: 600
  3. Option C: 800
  4. Option D: 1000

Full question on page 7 of the official paper (PDF)

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Key idea: The worst case puts every positive in a different group, so as many groups as possible need five more tests.

Official answer: A

There are 1000 / 5 = 200 groups, so 200 kits test the mixed samples. Each positive group then needs 5 more kits. The most positive groups there can be is 100, one positive in each:

200 + 100 \times 5 = 700

Option (A).

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GATE 2023, Q.10

General Aptitude2 marksMCQ

A 100 cm × 32 cm rectangular sheet is folded 5 times. Each time, the long edge aligns with its opposite side. In the end, the folded sheet is a rectangle of 100 cm × 1 cm. How many creases are visible when the sheet is unfolded?

  1. Option A: 32
  2. Option B: 5
  3. Option C: 31
  4. Option D: 63

Full question on page 8 of the official paper (PDF)

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Key idea: Each fold halves the 32 cm side, and in the end the creases split it into 1 cm strips.

Official answer: C

Five halvings take the 32 cm side to 32 / 2^5 = 1 cm. Unfolded, the sheet is divided into 32 strips of 1 cm, and 32 strips have 31 creases between them. Fold by fold, the creases add up as 1 + 2 + 4 + 8 + 16 = 31. Option (C).

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